A ship is twice as old as its boiler was when the ship was as old as the boiler is now. What is the ratio of the boiler’s age to the ship’s age?
Answer
Ratio is 3⁄4.
If we let S be the ship’s age and let B be the boiler’s age, and T to be the difference we get:
S – T = B
S = 2 x (B – T)
If we eliminate T (with T = S – B), we will get: B⁄S = 3⁄4